How to upload the image with it's encoding binary data?

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• Decode emoji from base64 string in java

  I want to send emoji from javascript to java and then send notification to both Android and IOS app using firebase cloud messaging. I am sending base64 string containing emojis from javascript to java servlet and in servlet when i decode that base64 string got question marks. Here is my javascript code for encoding message field and sent message to servlet.

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          error: function(error){
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      });
  }
  

  And Here is my servlet code.

  String message = URLDecoder.decode(request.getParameter("message"),"UTF-8");
  byte[] data = Base64.decode(message, Base64.DEFAULT);
  message = new String(data, "UTF-8");
  

  In message field i got the question marks. Any Help would be appreciated. Thanks.
• Retrofit upload Base64 string as a Field (8MB) takes 4 minutes

  I am trying to send the converted file (Base64 - String) as a parameter in POST, the file is about 8 MB, but sending takes about 4 minutes. Is there a way to speed up?

  Interface:

  @FormUrlEncoded
  @POST("upload")
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  Retrofit instance:

  public class RetrofitClientInstance {
  
  private static Retrofit retrofit;
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      Api api = RetrofitClientInstance.getRetrofitInstance(SharedUtils.SERVER_URL).create(Api.class);
  
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      request.enqueue(new Callback<Upload>() {
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          public void onFailure(Call<Upload> call, Throwable t) {
  
          }
      });
  }
  
• Python EXIF extraction gives error with Android photos

  I am trying to extract the EXIF metadata information from an image sent to the Google Cloud as a base64 string from a phone with this code:

  imgdata = base64.b64decode(str(base64_string)) 
  image = Image.open(io.BytesIO(imgdata))
  for orientation in ExifTags.TAGS.keys() : 
      if ExifTags.TAGS[orientation]=='Orientation': 
          break 
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  Although the above code seems to work for IOS, it crashes with Android photos giving AttributeError: 'NoneType' object has no attribute 'items' on the last line:

  exif=dict(image._getexif().items())
  

  I know that I can check if ._getexif() is None or not before trying to access it, but why do you think this error is happening? Is it related to how Android stores the EXIF information? Any help is appreciated.
• python post request input type = submit

  I want to access a following page in a browser with python and I can only click on the object below. Is there a solution that relies on "requests" and not on selenium?

  below is the html I inspected with Chrome Dev Tools.

  enter image description here

  The picture shows I am on the page with results 31-40, I want to access the page with 41-50 or 21-30. Help is appreciated.
• Python: Get OAuth2 token with `requests_oauthlib.OAuth2` and `requests.request` only

  I want to retrieve an OAuth2 token for an API. I have a Client ID and a Client secret. This approach from the requests_oauthlib documentation works:

  from oauthlib.oauth2 import BackendApplicationClient
  from requests.auth import HTTPBasicAuth
  from requests_oauthlib import OAuth2Session
  
  client_id = '12345'
  client_secret = '123456789'
  
  auth = HTTPBasicAuth(client_id, client_secret)
  client = BackendApplicationClient(client_id=client_id)
  oauth = OAuth2Session(client=client)
  token = oauth.fetch_token(
      token_url='https://api.districtm.ca/oauth/token',
      auth=auth
  )
  

  But it seems terribly complicated; if something ever goes wrong, I will have to wade through a deep mud of third-party code. Is there a way to retrieve the token using simpler methods like requests_oauthlib.OAuth2 and requests.request?

  I found a solution for Facebook's API that uses only requests.get and tried to adapt it:

  requests.post(
      'https://api.districtm.ca/oauth/token',
      params={
          'grant_type': 'client_credentials',
          'client_id': client_id,
          'client_secret': 'client_secret'
      },
      headers={
          'content-type': 'application/json'
      }
  )
  

  But this returns a HTTP 401 Unauthorized status code. I also played around with requests_oauthlib.OAuth2 but did not manage to find out what the authorization_url should be in my case.
• python read/write to file login script

  I was wondering if anyone would help. I am new to python. I am trying to create a basic login script for a game, that will write a username and password to a text file. When logging in, it will read from that text file and compare the entry made by the user. The code is below:

  def Register():
      print("Hello! You need to register an account before you can begin")
      username = input("Please enter a username: ")
      password = input("Now please enter a password: ")
      file = open("Login.txt","a")
      file.write (username)
      file.write (",")
      file.write (password)
      file.write("\n")
      file.close()
      print ("Your login details have been saved. ")
      print("You will now need to login")
      Login() 
  
  def Login():
      print("Please enter your details to log in")
      username1 = input("Please enter your username: ")
      password1 = input("Please enter your password: ")
  
      file = open("Login.txt","r")
  
      for row in file:
          field = row.split(",")
          username = field[0]
          password = field[1]
          lastchar = len(password)-1
          password = password[0:lastchar]
          print(username,password)
  
          if username1 == username and password1 == password:
              print("Hello",username)
  
          else:
              print("incorrect")
  
  #file.close()
  
  
   user=input("Are you already a user? ")
  
   if user == "Yes":
       Login()
  
   elif user =="No":
       Register()
  
   print("Welcome to our game")
  

  I have entered the second user who is stored in the text file, It seems to be working but it checks my first entry and says its incorrect and then loops to the second entry. This is the output I keep getting:

  Are you already a user? Yes
  Please enter your details to log in
  Please enter your username: jen
  Please enter your password: ben
  tess bess
  incorrect
  jen ben
  Hello jen
  Welcome to the dice game
  >>> 
  

  Does anyone have an idea on how to only display the entry you have entered?

  Thanks