How to set default python interpreter in pycharm
Every-time i start Pycharm i need to tell it what is my default interpreter. But it forgets and asks against after restarting the program. Is there anyway i can set it so that PyCharm would remember what my default interpreters was so I don't need to specify it when i restart the software?
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Add new row based on an if condition via Python
I need to add a new row if two consecutive cells of the column
doorare the same and the difference between two consecutive cells in the column
timeis more than 5 minutes. df:
Time door name 09:10:00 RDC_OUT-1 alex 09:10:00 RDC_OUT-1 alex 11:23:00 RDC_IN-1 alex 12:13:00 RDC_IN-1 alex 12:39:00 RDC_OUT-1 alex 15:23:00 RDC_IN-1 alex
import pandas as pd import numpy as np file_name='test.xlsx' from datetime import timedelta import datetime df = pd.read_excel(file_name, header=0, index= False) df= df.sort_values(by='Time') df.reset_index(inplace = True) print(df) idx= for i in range (0,len(df)): if i == 0: print ('Door Name '+str(i)+' ok') elif df['Door Name'][i] != df['Door Name'][i-1]: print('index '+str(i)+' ok') elif ((df['Door Name'][i] == df['Door Name'][i-1]) & ((df['Time'].iloc[i] - df['Time'].iloc[i-1]) > datetime.timedelta(minutes=5))): print('index '+str(i)+' ok') df.iloc[i] = [i,'RDC_OUT-1', str('12:00:00'), 'ARYA'] elif ((df['Door Name'][i] == df['Door Name'][i-1]) & ((df['Time'].iloc[i] - df['Time'].iloc[i-1]) < datetime.timedelta(minutes=5))): print('index '+str(i)+' nok') idx.append(i) print('idx\n',idx) df.drop(df.index[[idx]],inplace=True) print('\n',df)
Time door name Time door name 09:10:00 RDC_OUT-1 alex 11:23:00 RDC_IN-1 alex 12:00:00 RDC_OUT-1 ARYA 12:13:00 RDC_IN-1 alex 12:39:00 RDC_OUT-1 alex 15:23:00 RDC_IN-1 alex
0 4 09:10:00 RDC_OUT-1 alex 2 3 11:23:00 RDC_IN-1 alex 3 2 12:13:00 RDC_IN-1 alex 4 3 12:00:00 RDC_OUT-1 ARYA 5 0 15:23:00 RDC_IN-1 alex
Change the color of road in google map
How to change a google map particular road color using django framework? is this possible? I did side search about it but i can't find any solution for this, so any one have solution for this?.
Having trobule with sys.argv()
I'm creating a menu driven python script but I also want to add the functionality for command line arguments, for example if user has to select 2nd option he can either do it normal way i.e pressing 2 when asked to enter choice or to directly choose 2 by passing command line argument.
For this, am using
sysmodule. And checking if user has passed any command line argument if not, then calling the function which would print the options and ask user to enter his choice (the normal way as mentioned above)
As per example command would be
$ python3 choice.py 2
But am getting error while doing this and can't figure out what is wrong, here is the way am doing.
import sys . . . if sys.argv: if sys.argv1 == 1: choose_one() elif sys.argv == 2: choose_two() elif sys.arg == 3: choose_three() else: choose_option() #If none of these command line args then call the function which would print options and let user choose
File "choice.py", line 3, in <module> if sys.argv: IndexError: list index out of range
Basically I am willing to give user both options if he wants to run things quickly he can pass command line arguments, bypassing the usual reading choice option and entering the choice.
my pycharm and found that my remote interpreter was gone,I tried to add again by hand, but clicking add Remote didn't respond
After I reset my cloud server password.My pycharm reopened to find that the interpreter for my remote connection had disappeared,when I tried to open the project file for manual reconfiguration, I couldn't click add Remote,how to do?
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PyCharm IntelliSense is not working with streamz lib
I have the following problem. PyCharm does not offer auto-completion for the streamz lib.
In Jupyter notebook I get the desired function displayed:
I have tested it in PyCharm and IntelliJ, both code completion does not work correctly. The project interpreter in PyCharm is correctly selected
venv\Scripts\python.exe, the package is also shown to me.
Does anyone know any advice?
How can I implement the dynamic type of a python interpreter by oriented-object method?
I know it can be done by simply creating an
Objectclass and inherit all the types from it and using runtime check to determine the specific type. But it required a lots of
ifstatements, which seems a little bit naive and complex.
I try to overload the operator in a virtual function, but have difficulties making the parameters in base class coincidence with the parameters in derived class.
I wonder if there is any other wiser method? Thanks in advance.
Recommendations for Interpreter design inside of Python
I have had decent experience with Python, and I am wishing to create my own interpreted language within it. I understand the concept of lexers, parser, etc, and I am asking, is there are any modules (Compatible with Python 3.8.0) that would provide me with a easier interface to tokenize and handle very simple string parsing? I have looked at many, but they are either overly complex and/or are built revolving Python 2.x.x.
How to unmask the variable _ in python once it is masked with local variable in python interpreter
I am starting python and doing some calculations in the python interpreter, calculation results are stored in read only built-in variable
_. However when I declared a variable with name
_, the earlier one is masked. Now results are not stored in
_. How do I un-mask it. See the example I gave
before down voting, try to understand the question
>>> 3+5 8 >>> _ 8 >>>_ = 3 >>> 4*3 12 >>>4+4 8 >>> _ 3
from this time, calculation results are not stored in
_The question is how to get evaluated results to be stored in
_from this afterwards
Thank you @Matthias, you answered my question to use
>>> del _