Undefined Index: Gambar in proses_tambah on line 11

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• Select XML file and delete it after submit

  As for an assignment I'll have to select an XML file from a specific folder and remove it by clicking a button. So far I've tried everything I could find on the internet and the document still remains in the folder.

  (I'm still a student, so apologies in advance if there's a clear solution)

  Test example code

  <form method="POST" enctype="multipart/form-data">
      <input type="file" name="file">
      <input type="submit" value="Delete">
  </form>
  
  <?php 
  
  if (isset($_POST['submit'])) {
  $file = $_Files["file"];
  
  unlink("s_orderlist/". $file["name"]);
  
  }
  ?>
  

  Edit After your helpful comments I'm going to try a different approach that's more server friendly. Thank you!
• Changing image every 5-10 seconds

  Ok, so, I am trying to get a profile picture to change every couple of seconds on my website. It is written in php/css. I've read over 100 different posts and websites and have tried a dozen different ways to get this to work, but nothing I've tried works. Even if the coding works in places like JSFiddle, I cannot get it to work on my site. I have tried jQuery, cycles, cycles2, plain css and multiple types of each.

  code from module

  <div class="col-6 col-md-4">
  <div class="fling-minislide">
  <img src="<?=SITE_URL;?>/img/lapis.webp" class="lazy rounded-circle staff" alt="Slide 2"/>
  <img src="<?=SITE_URL;?>/img/dragon.webp" class="lazy rounded-circle staff" alt="Slide 1"/>
      </div>
  <p class="staff-name">theLapisFox</p>
  <p class="staff-role">Developer</p>
  </div>
  

  css code

  .fling-minislide {width:350px; height:300px; overflow:hidden; position:relative; }
  .fling-minislide img{ position:absolute; animation:fling-minislide 20s infinite; opacity:0; width: 100%; height: auto;}
  
  @keyframes fling-minislide {25%{opacity:1;} 40%{opacity:0;}}
  .fling-minislide img:nth-child(2){animation-delay:0s;}
  .fling-minislide img:nth-child(1){animation-delay:10s;}
  

  I got the above from https://www.hyde-design.co.uk/joomla-bites/80-create-a-css-slideshow-no-javascript-required and, while it, plus all the other solutions I've tried, works just fine for them, instead of getting a slideshow, both images are shown on screen when adding the code to my site.

  I know there are hundreds of questions on this board alone asking about this same exact issue, I've read most of them, but for some reason, it just refuses to work for me and I hope someone can tell me what could possibly be the issue.

  Edit:

  As further proof of other ways I have tried; http://jsfiddle.net/52RHm/ When adding it to my site, it didn't work either, but yet it works just fine in JSFiddle.
• Display Blog-Post on another side using PHP

  I have a problem with the PHP syntax.

  I try to create a Blog-System. The idea is that someone click on a special blogpost and then get linked to page called view.php. On that page only that blogpost should display witch the user clickt on.

  I managed to get the id of the blogpost within the url to the view.php page (e.g. view.php?id=21). The problem is that I dont use a form on my index to display all posts, so I think the $_GET varible doesn't work. I believe that a have to use a combination of the var_dump(), parse_url() and parse_str() functions to retrieve the id of the blogpost on view.php in order to display only that specific post. I do not know how though. Maybe I can use the $_SERVER varible to get the data from the URL?

  This is my index.php:

  <?php while ($row = mysqli_fetch_assoc($result))  { ?>
      <div style="">
          <a href="view.php?id=<?php echo $row['idGallery']; ?>">
              <p><?= $row['titleGallery'] ?></p>
              <img class="img-fluid" src="<?= 'img/gallery/' . $row['imgFullNameGallery'] ?>" width="100" height="100" />
          </a>
          <p><?= $row['descGallery'] ?></p>
      </div>
  <?php } ?>
  

  And this is the view.php:

  <?php
  include_once "includes/dbh.inc.php";
  $BlogPostSQLPrepared = mysqli_prepare($conn, "SELECT idGallery AS id, titleGallery, descGallery, imgFullNameGallery, orderGallery WHERE id = ?");
  
  mysqli_stmt_bind_param($BlogPostSQLPrepared, "i", $_GET['id']);
  mysqli_execute($BlogPostSQLPrepared);
  
  $result = mysqli_stmt_get_result($BlogPostSQLPrepared);
  
  if($row = mysqli_fetch_array($result)){
      $Post[$row['id']]['titleGallery'] = $row['titleGallery'];
      $Post[$row['id']]['descGallery'] = $row['descGallery'];
      $Post[$row['id']]['orderGallery'] = $row['orderGallery'];
      $Post[$row['id']]['imgFullNameGallery'] = $row['imgFullNameGallery'];
  }
  
• vue hot reload works but refresh page doesn't

  I'm using vue2. I have a page listing members of my website. When I modify the code, the hot reloading works fine and my table displays fine. But when I refresh the page, the table is still fine (checked in VueJS devtools) but it doesn't display because the array I'm iterating becomes undefined. what should I do? weird bug isn't it? by the way I'm using props to pass the data to a 'listing' component.

  props: ['table'],
    name: 'ListTable',
    components : {
  //      UserCard
    },
    data() {
      return {
        items: [],
        currentSort: 'id',
        currentSortDir: 'asc',
        pageSize: 10,
        currentPage: 1
      }
    },
    mounted() {
      this.items = this.$props.table.rows; 
  // becomes undefined after page refresh, hot reloading works fine though
    },
  
• is there any way to convert HTML tag a to bbcode?

  Is there any way to convert HTML tag a to bbcode? I have a download link, the original name of the file is test.wav, but when I download I get demo.wav which is fine with HTML . But now I want this code in BBcode or other solution rather than bbcode. demo.wav
• Mysq l - Slow one update query in large table

  i have a three almost identical queries executed one by one in my app. Two of queries are executing fairly fast but one is much slower. Here are queries:

  update `supremeshop_product_attributes` set `id_step` = 899 where `id_step` = 1 and `id_product` = 32641
  540ms
  
  update `supremeshop_product_attributes` set `id_step` = 1 where `id_step` = 0 and `id_product` = 32641
  1.71s
  
  update `supremeshop_product_attributes` set `id_step` = 0 where `id_step` = 899 and `id_product` = 32641
  9.75ms
  

  

  Create table query

  CREATE TABLE `supremeshop_product_attributes` (
   `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
   `id_product` int(11) NOT NULL,
   `id_attribute` int(11) NOT NULL,
   `id_attribute_group` int(11) NOT NULL,
   `id_step` int(11) NOT NULL,
   `id_alias` int(9) NOT NULL,
   `price_retail` int(11) NOT NULL DEFAULT '0',
   `behaviour` int(1) NOT NULL DEFAULT '0',
   `active` int(1) NOT NULL DEFAULT '1',
   `created_at` timestamp NULL DEFAULT NULL,
   `updated_at` timestamp NULL DEFAULT NULL,
   PRIMARY KEY (`id`),
   KEY `supremeshop_product_attributes_id_product_index` (`id_product`),
   KEY `supremeshop_product_attributes_id_attribute_index` (`id_attribute`),
   KEY `supremeshop_product_attributes_id_attribute_group_index` (`id_attribute_group`),
   KEY `supremeshop_product_attributes_id_step_index` (`id_step`)
  ) ENGINE=InnoDB AUTO_INCREMENT=3012991 DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_unicode_ci
  

  

  Facts:

  • table has 1500000 rows
  • each query updates around 650 rows
  • each searched/updated field has index (id(primary), id_product, id_step, id_alias)
  • only second query takes much longer time to execute (everytime - even executed as single query not one by one)
  • each variable used in query is integer
  • if i execute queries direcly in phpymysql -> sql - i get the same execution time (like in my laravel app so query is somehow slow)

  Question is why? And is there a good explanation/ fix for that problem.

  For any help many thanks! Mark.
• Problem when Handling repeated error values on php and mysql

  I have a PHP program that connect to a MariaDB databse.

  I upload name as "numbers" and i defined the value as UNIQUE so I don´t want to be repeatated.

  However I would like to handle the error when a vlaue is repeated:

  This is the table I created:

  Table in MariaDB

  create table test(
      ->     id int NOT NULL AUTO_INCREMENT,
      ->     name varchar(255) UNIQUE,
      ->     date DATE NOT NULL,
      ->     PRIMARY KEY (id)
      -> );
  

  This is the script in PHP:

  $host = "localhost";
  $db_name = "xxx";
  $username = "xxx";
  $password = "xxx";
  $connection = null;
  $dt1=date("Y-m-d");
  try{
      $connection = new PDO("mysql:host=" . $host . ";dbname=" . $db_name, $username, $password);
      $connection->exec("set names utf8");
  }
  catch(PDOException $exception){
      echo "Connection error: " . $exception->getMessage();
  }
  function saveData($name, $dt1){
      global $connection;
      $query = "INSERT INTO test(name, date) VALUES( :name, :date )";
      $callToDb = $connection->prepare( $query );
      $name=htmlspecialchars(strip_tags($name));
      //$dt1=htmlspecialchars(strip_tags($dt1));
      $callToDb->bindParam(":name", $name);
      $callToDb->bindParam(":date", $dt1);
  
      if($callToDb->execute()){
  
          //return '<h3 style="text-align:center;">registration submmited!</h3>';
          //if (!$callToDb->execute()) {
          //    if ($callToDb->errno == 1062) {
          //    return '<h3 style="text-align:center;">VALUE REPEATED!</h3>';
          //    }
          //   else{
              return '<h3 style="text-align:center;">registration submmited!</h3>';
          //    }
          }
      }
  
  
      if( isset($_POST['submit'])) {
          $name = htmlentities($_POST['name']);
          $dt1 = htmlentities($_POST['date']);
          //then you can use them in a PHP function. 
          $result = saveData($name, $dt1);
          echo $result;
      }
      else{
          echo '<h3 style="text-align:center;">A very detailed error message</h3>';
      }
      //header("location:javascript://history.go(-1)");
  }
  

  the code part after if($callToDb->execute()){ it is commented because it is not working but I would like to just show a message when the vlaue is repeated. The same than when a vlaue is registrated correctly.

  The issue to handle duplicate error is in this part which at the moment I am not using in my code as is not working fine:

  if (!$callToDb->execute()) {
      if ($callToDb->errno == 1062) {
          return '<h3 style="text-align:center;">VALUE REPEATED!</h3>';
      }
      else{
         return '<h3 style="text-align:center;">registration submmited!</h3>';
      }
  }
  

  Any idea why this part of the code it is not working?
• UPDATE command in php and sql deleting database data

  I'm trying to get my database to update with new information submitted in a form. However, upon submission the field that should be updated is just emptied and the page always displays the message "incident description updated" regardless of whether the form has been submitted.

  My error reporting shows that $description is undefined when the page loads.

    <form method="POST">
        <label for="incidentid">Select Incident ID</label>
      <select name="incidentid" required>
          <option>Select ID</option>
          <?php
  
              $incidentlist = "SELECT * FROM Incident";
              $incidentid = mysqli_query($conn, $incidentlist);
  
              while($row = mysqli_fetch_array($incidentid)) {
                  echo '<option>'.$row['Incident_ID'].'</option>';
              }
          ?>
      </select>
        <label for="description">Edit Offence Description</label>
        <input type="text" name="description">
        <button type="submit">Retrieve and Edit</button>
    </form>
  
  <?php
  if ($_POST['description']!="" && $_POST['incidentid']!="") {
      $retrieve = $_POST['incidentid'];
      $description = $_POST['description'];
  
      $sql_desc = mysqli_query($conn, "UPDATE Incident
              SET Incident_Report='$description'
              WHERE Incident_ID='$retrieve';");
      $sql_desc = mysqli_query($conn, "SELECT * FROM Incident
              WHERE Incident_REPORT='$description'
              AND Incident_ID='$retrieve';");
  
      if (mysqli_num_rows($sql_desc) > 0)
      {
          echo "<br/>";
          echo "Incident description updated.";
      }}
  
  ?>
  <br/>
  

  I'm using

  ini_set('display_errors', '1');
  ini_set('display_startup_errors', '1');
  error_reporting(E_ALL);
  

  for error messages. It tells me that $description is undefined, but this goes away when I send the form