how to get weeklytotal and yesterday record in mysql in one table
Hi Everyone i am trying to implement query to get weekly and yesterday data in same table, dummy output i have shared below, if yesterday not exist as per employee_id it should we showing 0 also as per my table week start from monday and end at sunday.please help me out how to query this get weekly_total and yesterday record and one table.
Table name-dailydata-
Sample data
employee_id | date | total |
---|---|---|
20 | 2022-04-25 | 10 |
20 | 2022-04-26 | 20 |
20 | 2022-04-27 | 20 |
20 | 2022-04-28 | 10 |
20 | 2022-04-29 | 20 |
20 | 2022-04-30 | 30 |
20 | 2022-04-31 | 40 |
20 | 2022-05-01 | 50 |
40 | 2022-04-26 | 20 |
expected output
employee_id | weekly_total | yesterday_record |
---|---|---|
20 | 200 | 40 |
40 | 20 | 0 |
mysql query to get weekly data
select employee_id,sum(total) as week_total from dailydata where date between '2022-04-25' and '2022-05-01'
4 answers
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answered 2022-05-07 06:07
Kendle
You can use a case in the query to get yesterdays data, as long as the where does not exclude it, which is the case in the second query.
Once you have understood the principal you can define the date range so that it is calculated dynamically when you run the script if what you want is to see yesterday's figure and the last 7 days total.
You can also get yesterday usingSUBDATE(NOW(),1)
which is shorter.select employee_id, sum(total) as week_total , sum(case when date = DATE_SUB(CURDATE(), INTERVAL 1 DAY) then total else 0 end as yesterday from dailydata where date between DATE_SUB(CURDATE(), INTERVAL 1 WEEK) and DATE_SUB(CURDATE(), INTERVAL 1 DAY) ;
select employee_id, sum(total) as week_total , sum(case when date = DATE_SUB(CURDATE(), INTERVAL 1 DAY) then total else 0 end as yesterday from dailydata where date between '2022-04-25' and '2022-05-01';
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answered 2022-05-07 06:09
Elisha John
--start of this week
SELECT DATEADD(wk, DATEDIFF(wk, 0, GETDATE()), 0)
--end of this week
SELECT DATEADD(wk, DATEDIFF(wk, 0, GETDATE()), 6)
--yesterday
select GETDATE() -1
--Your Qurey
select employee_id,sum(total) as week_total, (select sum(total) as week_total from dailydata b where [date] = CONVERT(date, GETDATE() -1 ) and a.employee_id = b.employee_id) as yesterday_record from dailydata a where [date] between DATEADD(wk, DATEDIFF(wk, 0, GETDATE()), 0) and DATEADD(wk, DATEDIFF(wk, 0, GETDATE()), 6) Group by employee_id
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answered 2022-05-07 06:10
D-Shih
You can try to use the condition aggregate function to make it.
We might add non-aggregate columns in the group by when we are using aggregate functions.
select employee_id, SUM(total) as week_total, SUM(CASE WHEN DATEDIFF('2022-05-01',date) = 1 THEN total ELSE 0 END) yesterday_record from dailydata t1 where date between '2022-04-25' and '2022-05-01' GROUP BY employee_id
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answered 2022-05-07 06:59
Meet Soni
Hope this may help you, You just need to use the aggregate function in the case of IFNULL.
DBFiddle URL: Click Here
For the start of the week
SELECT SUBDATE(CURDATE(), weekday(CURDATE())); --Start of week
For the end of the week
SELECT DATE(CURDATE() + INTERVAL (6 - WEEKDAY(CURDATE())) DAY); --End of week
Hereby SQL query for getting employe wise total and yesterday total. If yesterday's total doesn't exist so for that Have used IFNULL. Just used SUBDATE for getting the start and end of the week date by passing current date.
SELECT employee_id, IFNULL(SUM(total),0) AS total, IFNULL(SUM(CASE date WHEN subdate(CURDATE(), 1) THEN total ELSE 0 END),0) AS yesterday_total FROM dailydata WHERE date BETWEEN SUBDATE(CURDATE(), weekday(CURDATE())) AND (CURDATE() + INTERVAL (6 - WEEKDAY(CURDATE())) DAY) GROUP BY employee_id
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